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Help with specific heat question!?
A piece of chromium metal with a mass of 24.26g is heated in boiling water to 98.3C and then dropped into a coffee-cup calorimeter containing 82.3g of water at 23.3C. When thermal equilibrium is reached, the final temperature is 25.6C. Calculate the specific heat capacity of chromium.
I'm not sure how to set it up even. :\
1 Answer
- Caroline MillerLv 79 years agoFavourite answer
the heat lost by the metal = the heat gained by the water
mass Cr x c Cr x ∆TCr = mass water x c water x ∆T water
∆TCr ≠ ∆T water
24.26g x c x (98.3 - 25.6) = 82.3g x 4.184J/g-ºC x (25.6 - 23.3)
c = 0.449J/g-ºC
