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? asked in Science & MathematicsChemistry · 2 months ago

2A+3B→CΔHrxn=−173kJ Determine the amount of heat emitted. 1. 2mol a 2. 8 mol a 3. 4 mol b 4. 8 mol b?

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  • 1 month ago

    2A+3B→C ΔHrxn=−173kJ

    2 mole of A gives -173Kj

    1.2 moles of A gives = -173*1.2/2 = -103Kj

    2.8. moles of A gives = -173 * 2.8/2 = -242.2 kJ

    3 mole of B gives -173Kj

    3.4 moles of B gives = -173*3.4/3 = -196 Kj

    3 mole of B gives -173Kj

    4.8 moles of B gives = -173*4.8/3 = -276.8 KJ

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