A gardener has perimeter of 88 feet. The length is 2 feet more than the width. Find the length and width.?

given

l = w + 2

p = 88ft

P = 2(l + w)

88 = 2(w + 2 + w)

88 = 2(2w + 2)

88 = 4w + 4

88 - 4 = 4w

84 = 4w

w = 21 ft answer//

so

l = w + 2 =21 + 2 = 23 ft answer//

Remember the formula for the perimeter of a rectangle?

PERIMETER= 2W +2L

So, 2W+2L = 88

In this problem you are given that the length is 2 feet more than the width, therefore you can set up:

L = w + 2

Now, all you have to do is plug in the equation for L (length) into 2W+2L = 88, then solve

2W + 2(W+2) = 88

2W+2W+4 = 88

4W + 4 = 88

4W = 84

W= 21

So we got that our width is 21 feet, now we find the length

L = 21 + 2 = 23 ft

Answer = LENGTH = 23 ft; WIDTH = 21 ft

here,

total perimeter = 88 ft

let width be x then,

length = (x + 2) and width = x

now, perimeter = l+w

88 = x+2+x

88 = 2x+2

88 = 2(x+1)

(x+1) = 88/2

(x+1) = 44

x = 44-1 = 43 is the width.

for length, as its 2 more than width = 2+43=45

To check answer, l+w = 45+43 = 88 ans.

(w + 2) + (w + 2) + (w) + (w) = 88

4w + 4 =88

4w + 4 - 4 = 88 - 4

4w ÷ 4 = 84 ÷ 4

w = 21