How to transpose/rearrange these equations?

If X is the subject, only x should be on one side of the equation and there shouldn't be any x on the other side......

1) ax+b=bx

ax - bx = b

x(a-b) = b

x = b/(a-b)

2) (x/a) - 1 = (x/b) + 2

x/a - x/b = 2 + 1

x (1/a - 1/b) = 3

x (b-a)/ab = 3

x = 3ab/(b-a)

Make 'x' the subject

1) ax+b=bx

ax = bx - b = b(x-1)

(x-1)/x = a/b

1-1/x = a/b

1/x = 1-a/b = (b-a)/b

Therefore x = b/(b-a) >>>>>>>>>>Answer

2) (x/a) - 1 = (x/b) + 2

(x/a) - (x/b) = 3

x(b-a)/ab = 3

x = 3ab/(b-a) >>>>>>>>>>>Answer

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if x were to be the subject is it ok if x is on the other side of the equation too?

for example, my answer for 1) was x= (bx-b)/a where x was before and after the equal sign.

This is wrong. When x is to be the subject, you have to express the value of x in terms of the other variable or variables. Therefore LHS should be x only. There should not be any x in the RHS.

First i detect it greater uncomplicated to rewrite something that isnt grouped mutually, consequently, the water. MgCO3 + HCl --> MgCl2 + H2O + CO2 First shall we start up with balancing the hydrogens and spot the place we stand. There are 2 hydrogens on the acceptable area, and between the left... so shall we make it 2 on the left. MgCO3 + 2HCl --> MgCl2 + H2O + CO2 shall we see if something isn't balanced. Left area / stunning area Mg: a million/a million C: a million/a million O: 3/3 H: 2/2 Cl: 2/2 appears like we are all balanced, so your very final, balanced equation is: MgCO3 + 2HCl --> MgCl2 + H2O (or HOH, same element) + CO2 *Sorry for the postpone in answering your question, YA has been down

I'm not sure what you mean by make 'x' the subject, but what I always learned is that you are solving for 'x', if this is true in this case, then your answer would be:

1.) x= ax/b + 1

not sure about #2

1) ax+b=bx

ax - bx = -b

x(a - b) = -b

x = -b/(a - b) ---> final answer!

2) (x/a) - 1 = (x/b) + 2

(x/a) - (x/b) = 3

x(b-a)/ab = 3

x = 3ab/(b-a) ---> final answer!

1) ax+b=bx

ax-bx=-b

x(a-b)=-b

.......-b

x=-------- answer//

.....(a-b)

.....x...........x

2)[------ - 1=-------+2]ab

.....a............b

bx-ab=ax+2ab

bx-ax=2ab+ab

x(b-a)=3ab

.....3ab

x=-------- answer//

.....b-a