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Find the equation of the tangent to the graph?
f(x) = 4/x (ln(x^2)-1)
Determine the value of m for which the line with the equation y=mx is tangent to the graph of f.
OMG - this is giving me the shits. Can someone provide me a step by step answer to this? Thanks.
Update:
(4/x)(ln(x^2)-1) to be more specific
1 Answer
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- 1 decade agoFavourite answer
Find out slope of the curve i.e dy/dx. Now if y=mx is the tangent of that graph then, m=dy/dx.
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