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We are told simply to simplify the following math expression.?
Simplify
tan(A) / [sec(A) - cos (A)]
thanks in advanced.
3 Answers
- Anonymous1 decade agoFavourite answer
Here's how you get the answer:
tan(A)
--------
[sec(A) - cos (A)]
sin(A) 1
--------- = tan(A) sec(A) = -------
cos(A) cos(A)
Substitue these
sin(A)/cos(A)
-------------------
1/cos(A) - cos(A)
Multiply everything by cos(A)
sin(A)
---------------
1 - cos^2(A)
Use 1 - cos^2(A) = sin^2(A) and substitute
sin(A)
---------
sin^2(A)
Simplify
1
--------
sin(A)
Hope This Helps,
Crowder
- gôhpihánLv 71 decade ago
sec A - cos A
= 1/ cosA - cos A
= (1 - cos² A) / cos A
= sin² A / cos A
tan A / ( sec A -cos A)
= tan A / (sin²A / cosA)
= tanA cosA / sin² A
= sin A/ cosA * cos A / sin² A
= sinA / sin² A
= 1/ sin A
= cosec A
- 1 decade ago
[tan(A)] / [sec(A) - cos(A)]
[tan(A)] / [(1/Cos) - cos(A)]
[tan(A)] / [(1-cos^A) / cos(A)]
[tan(A) cos(A)] / [1 - cos^(A)]
[tan(A) cos(A)] / [sin^(A)]
[Sin(A) / cos(A)] cos(A) / [sin^(A)]
[sin(A)] / [sin^(A)]
1 / [sin(A)]
= CosecA