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We are told simply to simplify the following math expression.?

Simplify

tan(A) / [sec(A) - cos (A)]

thanks in advanced.

3 Answers

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  • Anonymous
    1 decade ago
    Favourite answer

    Here's how you get the answer:

    tan(A)

    --------

    [sec(A) - cos (A)]

    sin(A) 1

    --------- = tan(A) sec(A) = -------

    cos(A) cos(A)

    Substitue these

    sin(A)/cos(A)

    -------------------

    1/cos(A) - cos(A)

    Multiply everything by cos(A)

    sin(A)

    ---------------

    1 - cos^2(A)

    Use 1 - cos^2(A) = sin^2(A) and substitute

    sin(A)

    ---------

    sin^2(A)

    Simplify

    1

    --------

    sin(A)

    Hope This Helps,

    Crowder

  • 1 decade ago

    sec A - cos A

    = 1/ cosA - cos A

    = (1 - cos² A) / cos A

    = sin² A / cos A

    tan A / ( sec A -cos A)

    = tan A / (sin²A / cosA)

    = tanA cosA / sin² A

    = sin A/ cosA * cos A / sin² A

    = sinA / sin² A

    = 1/ sin A

    = cosec A

  • 1 decade ago

    [tan(A)] / [sec(A) - cos(A)]

    [tan(A)] / [(1/Cos) - cos(A)]

    [tan(A)] / [(1-cos^A) / cos(A)]

    [tan(A) cos(A)] / [1 - cos^(A)]

    [tan(A) cos(A)] / [sin^(A)]

    [Sin(A) / cos(A)] cos(A) / [sin^(A)]

    [sin(A)] / [sin^(A)]

    1 / [sin(A)]

    = CosecA

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